What is the answer to (y-6)^2-(y+4)^2+55=0 ?

The answer to (y-6)^2-(y+4)^2+55=0 is y= 15/4

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(y-6)^2-(y+4)^2+55=0

(y - 6)^{2} - (y + 4)^{2} + 55 = 0

y = \frac{15}{4}

Decimal Notation

y = 3.75

Solution steps

(y - 6)^{2} - (y + 4)^{2} + 55 = 0

Move

55

to the right side

(y - 6)^{2} - (y + 4)^{2} = - 55

Expand

(y - 6)^{2} - (y + 4)^{2} : - 20 y + 20

- 20 y + 20 = - 55

Move

20

to the right side

- 20 y = - 75

Divide both sides by

- 20

y = \frac{15}{4}

19 - 4 c = 17

9 (x - 2) = 3 x + 6

p - 3 = - 4

\frac{3}{7} = \frac{x}{21}

12 - \frac{4}{5} (x + 15) = \frac{2}{5} x + 6

What is the answer to (y-6)^2-(y+4)^2+55=0 ?
The answer to (y-6)^2-(y+4)^2+55=0 is y= 15/4
Solve for y: (y-6)^2-(y+4)^2+55=0
The solution is y= 15/4