What is the answer to (x+5)^2+7=(x-2)^2 ?

The answer to (x+5)^2+7=(x-2)^2 is x=-2

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(x+5)^2+7=(x-2)^2

(x + 5)^{2} + 7 = (x - 2)^{2}

x = - 2

Solution steps

(x + 5)^{2} + 7 = (x - 2)^{2}

Expand

(x + 5)^{2} + 7 : x^{2} + 10 x + 32

Expand

(x - 2)^{2} : x^{2} - 4 x + 4

x^{2} + 10 x + 32 = x^{2} - 4 x + 4

Move

32

to the right side

x^{2} + 10 x = x^{2} - 4 x - 28

Subtract

x^{2} - 4 x

from both sides

x^{2} + 10 x - (x^{2} - 4 x) = x^{2} - 4 x - 28 - (x^{2} - 4 x)

Simplify

14 x = - 28

Divide both sides by

14

x = - 2

x, - 3 x + 5 y = 15

x, - 3 x + 3 y = 4

5 x + 20 = 10

x, 2 x - y - 5 = 0

- 3 x - 4 + 2 x = 2

What is the answer to (x+5)^2+7=(x-2)^2 ?
The answer to (x+5)^2+7=(x-2)^2 is x=-2
Solve for x: (x+5)^2+7=(x-2)^2
The solution is x=-2