What are the solutions to the equation 5t^2-6t+600=0 ?

The solutions to the equation 5t^2-6t+600=0 are t= 3/5+i(sqrt(2991))/5 ,t= 3/5-i(sqrt(2991))/5

Find the zeros of 5t^2-6t+600=0

The zeros of 5t^2-6t+600=0 are t= 3/5+i(sqrt(2991))/5 ,t= 3/5-i(sqrt(2991))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 t^{2} - 6 t + 600 = 0

t = \frac{3}{5} + i \frac{2991}{5}, t = \frac{3}{5} - i \frac{2991}{5}

Solution steps

5 t^{2} - 6 t + 600 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 5 \cdot 600}{2 \cdot 5}

Simplify

(- 6)^{2} - 4 \cdot 5 \cdot 600 : 22991 i

t_{1, 2} = \frac{- ( - 6 ) \pm 2 2991 i}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 2 2991 i}{2 \cdot 5}, t_{2} = \frac{- ( - 6 ) - 2 2991 i}{2 \cdot 5}

t = \frac{- ( - 6 ) + 2 2991 i}{2 \cdot 5} : \frac{3}{5} + i \frac{2991}{5}

t = \frac{- ( - 6 ) - 2 2991 i}{2 \cdot 5} : \frac{3}{5} - i \frac{2991}{5}

The solutions to the quadratic equation are:

t = \frac{3}{5} + i \frac{2991}{5}, t = \frac{3}{5} - i \frac{2991}{5}

x - 1 = 7 (x - 5) - (6 x - 4)

∣ 10 - z ∣ = 5

y^{- 4} \cdot y^{3}

- 3 (2 x + 1) > - 2 (x + 4)

e^{\frac{7}{2}}

What are the solutions to the equation 5t^2-6t+600=0 ?
The solutions to the equation 5t^2-6t+600=0 are t= 3/5+i(sqrt(2991))/5 ,t= 3/5-i(sqrt(2991))/5
Find the zeros of 5t^2-6t+600=0
The zeros of 5t^2-6t+600=0 are t= 3/5+i(sqrt(2991))/5 ,t= 3/5-i(sqrt(2991))/5