What is the answer to (x+2}{12}-(2x-3)/9 =\frac{4-3x)/(18)+x/6 ?

The answer to (x+2}{12}-(2x-3)/9 =\frac{4-3x)/(18)+x/6 is x=2

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(x+2}{12}-(2x-3)/9 =\frac{4-3x)/(18)+x/6

\frac{x + 2}{12} - \frac{2 x - 3}{9} = \frac{4 - 3 x}{18} + \frac{x}{6}

x = 2

Solution steps

\frac{x + 2}{12} - \frac{2 x - 3}{9} = \frac{4 - 3 x}{18} + \frac{x}{6}

Multiply by LCM

3 (x + 2) - 4 (2 x - 3) = 2 (- 3 x + 4) + 6 x

Expand

3 (x + 2) - 4 (2 x - 3) : - 5 x + 18

Expand

2 (- 3 x + 4) + 6 x : 8

- 5 x + 18 = 8

Move

18

to the right side

- 5 x = - 10

Divide both sides by

- 5

x = 2

x, x - \frac{3 x + 4}{7} = \frac{y + 2}{3}

\frac{9}{5} x + 5 = x + 8

x, 4 x + 3 y = 22

y, x = \frac{y}{z}

b, a = \frac{b}{c}

What is the answer to (x+2}{12}-(2x-3)/9 =\frac{4-3x)/(18)+x/6 ?
The answer to (x+2}{12}-(2x-3)/9 =\frac{4-3x)/(18)+x/6 is x=2
Solve for x: (x+2}{12}-(2x-3)/9 =\frac{4-3x)/(18)+x/6
The solution is x=2