What is the answer to solvefor y,x^3-3x^2y=c ?

The answer to solvefor y,x^3-3x^2y=c is y=-(c-x^3)/(3x^2);\quad x\ne 0

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solvefor y,x^3-3x^2y=c

solve for

y, x^{3} - 3 x^{2} y = c

y = - \frac{c - x ^{3}}{3 x ^{2}}; x \neq = 0

Solution steps

x^{3} - 3 x^{2} y = c

Move

x^{3}

to the right side

- 3 x^{2} y = c - x^{3}

Divide both sides by

- 3 x^{2}; x \neq = 0

y = - \frac{c - x ^{3}}{3 x ^{2}}; x \neq = 0

5 (x + 2) = - 2 (x + 2) + 7

x, 7 x - 4 y = 28

(5 y + 6) 2 = 24

\frac{1}{2} t - \frac{2}{3} = \frac{1}{6} + \frac{2}{3} t

a, (a + b) (a - b) = a^{2} - b^{2}

What is the answer to solvefor y,x^3-3x^2y=c ?
The answer to solvefor y,x^3-3x^2y=c is y=-(c-x^3)/(3x^2);\quad x\ne 0