What are the solutions to the equation 5x^2+7x+4=0 ?

The solutions to the equation 5x^2+7x+4=0 are x=-7/10+i(sqrt(31))/(10),x=-7/10-i(sqrt(31))/(10)

Find the zeros of 5x^2+7x+4=0

The zeros of 5x^2+7x+4=0 are x=-7/10+i(sqrt(31))/(10),x=-7/10-i(sqrt(31))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + 7 x + 4 = 0

x = - \frac{7}{10} + i \frac{31}{10}, x = - \frac{7}{10} - i \frac{31}{10}

Solution steps

5 x^{2} + 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

Simplify

7^{2} - 4 \cdot 5 \cdot 4 : 31 i

x_{1, 2} = \frac{- 7 \pm 31 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 31 i}{2 \cdot 5}, x_{2} = \frac{- 7 - 31 i}{2 \cdot 5}

x = \frac{- 7 + 31 i}{2 \cdot 5} : - \frac{7}{10} + i \frac{31}{10}

x = \frac{- 7 - 31 i}{2 \cdot 5} : - \frac{7}{10} - i \frac{31}{10}

The solutions to the quadratic equation are:

x = - \frac{7}{10} + i \frac{31}{10}, x = - \frac{7}{10} - i \frac{31}{10}

x^{2} - 18 x + 56 = 0

4 x^{2} - 12 x + 11 = 0

10 y - 14 \geq - 13

\frac{5}{2} \cdot \frac{4}{9}

\frac{1}{2} x - 4 \leq - 9 - \frac{1}{3} x

What are the solutions to the equation 5x^2+7x+4=0 ?
The solutions to the equation 5x^2+7x+4=0 are x=-7/10+i(sqrt(31))/(10),x=-7/10-i(sqrt(31))/(10)
Find the zeros of 5x^2+7x+4=0
The zeros of 5x^2+7x+4=0 are x=-7/10+i(sqrt(31))/(10),x=-7/10-i(sqrt(31))/(10)