What is the answer to 2+4x-10+6x=2(5x-4) ?

The answer to 2+4x-10+6x=2(5x-4) is True for all x

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2+4x-10+6x=2(5x-4)

2 + 4 x - 10 + 6 x = 2 (5 x - 4)

True for all x

Solution steps

2 + 4 x - 10 + 6 x = 2 (5 x - 4)

Group like terms

4 x + 6 x + 2 - 10 = 2 (5 x - 4)

Add similar elements:

4 x + 6 x = 10 x

10 x + 2 - 10 = 2 (5 x - 4)

Add/Subtract the numbers:

2 - 10 = - 8

10 x - 8 = 2 (5 x - 4)

Expand

2 (5 x - 4) : 10 x - 8

10 x - 8 = 10 x - 8

Move

8

to the right side

10 x = 10 x

Move

10 x

to the left side

0 = 0

Both sides are equal

True for all x

\frac{2}{7} = \frac{x}{42}

4 (x - 7) = 0.3 (x + 2) + 2.11

\frac{4 x + 5}{8} - \frac{8 x - 3}{6} + \frac{5 - 3 x}{3} = \frac{3 + 5 x}{2} + \frac{3}{4}

- \frac{x}{5} + \frac{11 x}{5} - 1 = 21

a, x^{2} + 4 y^{2} = 4 a y

What is the answer to 2+4x-10+6x=2(5x-4) ?
The answer to 2+4x-10+6x=2(5x-4) is True for all x
Solve for x: 2+4x-10+6x=2(5x-4)
The solution is True for all x