What is the answer to solvefor p,x^2+px+q=0 ?

The answer to solvefor p,x^2+px+q=0 is p=(-x^2-q)/x ;\quad x\ne 0

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solvefor p,x^2+px+q=0

solve for

p, x^{2} + p x + q = 0

p = \frac{- x ^{2} - q}{x}; x \neq = 0

Solution steps

x^{2} + p x + q = 0

Move

x^{2}

to the right side

p x + q = - x^{2}

Move

q

to the right side

p x = - x^{2} - q

Divide both sides by

x; x \neq = 0

p = \frac{- x ^{2} - q}{x}; x \neq = 0

11 x + 6 = 83

2 = - \frac{3}{10} y - 7

lo g_{25} (5) = x

\frac{1}{4} k + 3 = - 5

x, x - 2 y + 2 = 0

What is the answer to solvefor p,x^2+px+q=0 ?
The answer to solvefor p,x^2+px+q=0 is p=(-x^2-q)/x ;\quad x\ne 0