What is the answer to solvefor j,j(x)=(4x^2-3)/(x^2-2x) ?

The answer to solvefor j,j(x)=(4x^2-3)/(x^2-2x) is j=(4x^2-3)/(x(x^2-2x));\quad x\ne 0

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solvefor j,j(x)=(4x^2-3)/(x^2-2x)

solve for

j, j (x) = \frac{4 x ^{2} - 3}{x ^{2} - 2 x}

j = \frac{4 x ^{2} - 3}{x ( x ^{2} - 2 x )}; x \neq = 0

Solution steps

j (x) = \frac{4 x ^{2} - 3}{x ^{2} - 2 x}

Divide both sides by

x; x \neq = 0

j = \frac{4 x ^{2} - 3}{x ( x ^{2} - 2 x )}; x \neq = 0

8 (x - 3) + 14 = 2 (4 x + 5)

x, 5 x + y = 11

- 0.03 n = - 0.01 (2 n + 3)

\frac{- 2}{6} = \frac{3 c}{9}

\frac{1}{3} + \frac{x}{2} = - \frac{x}{3} + \frac{1}{4}

What is the answer to solvefor j,j(x)=(4x^2-3)/(x^2-2x) ?
The answer to solvefor j,j(x)=(4x^2-3)/(x^2-2x) is j=(4x^2-3)/(x(x^2-2x));\quad x\ne 0