What are the solutions to the equation 12=a^2 ?

The solutions to the equation 12=a^2 are a=2sqrt(3),a=-2sqrt(3)

Find the zeros of 12=a^2

The zeros of 12=a^2 are a=2sqrt(3),a=-2sqrt(3)

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12 = a^{2}

a = 23, a = - 23

Decimal Notation

a = 3.46410 \dots, a = - 3.46410 \dots

Solution steps

12 = a^{2}

Switch sides

a^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 12, a = - 12

12 = 23

- 12 = - 23

a = 23, a = - 23

4 (2 x - 4) - 5 x + 4 = - 30

s^{2} - s - 12 = 0

0 \leq 4 - \frac{1}{3} x \leq 2

27 x^{2} - 36 x + 12

\frac{0.9 + 2}{( 0.9 - 1 ) ^{2}}

What are the solutions to the equation 12=a^2 ?
The solutions to the equation 12=a^2 are a=2sqrt(3),a=-2sqrt(3)
Find the zeros of 12=a^2
The zeros of 12=a^2 are a=2sqrt(3),a=-2sqrt(3)