What is factor 49x^2+28xy+4y^2 ?

The solution to factor 49x^2+28xy+4y^2 is (7x+2y)^2

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factor 49x^2+28xy+4y^2

factor

49 x^{2} + 28 x y + 4 y^{2}

(7 x + 2 y)^{2}

Solution steps

49 x^{2} + 28 x y + 4 y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

49 x^{2} = (7 x)^{2}

4 y^{2} = (2 y)^{2}

28 x y = 2 \cdot 7 x \cdot 2 y

= (7 x)^{2} + 2 \cdot 7 x \cdot 2 y + (2 y)^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(7 x)^{2} + 2 \cdot 7 x \cdot 2 y + (2 y)^{2} = (7 x + 2 y)^{2}

= (7 x + 2 y)^{2}

16 x^{2} - 16 x + 5 = 0

- 61 - 15 x = 1 - 20 x + 38

6 (x - 9) = 18

8 x^{2} y z^{2} yz w 2 z w^{3}

50 - \frac{35}{5}

What is factor 49x^2+28xy+4y^2 ?
The solution to factor 49x^2+28xy+4y^2 is (7x+2y)^2