What is the answer to solvefor x,(x+y)^2=x^2+2xy+y^2 ?

The answer to solvefor x,(x+y)^2=x^2+2xy+y^2 is True for all x

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solvefor x,(x+y)^2=x^2+2xy+y^2

solve for

x, (x + y)^{2} = x^{2} + 2 x y + y^{2}

True for all x

Solution steps

(x + y)^{2} = x^{2} + 2 x y + y^{2}

Expand

(x + y)^{2} : x^{2} + 2 x y + y^{2}

x^{2} + 2 x y + y^{2} = x^{2} + 2 x y + y^{2}

Move

y^{2}

to the right side

x^{2} + 2 x y = x^{2} + 2 x y

Subtract

x^{2} + 2 x y

from both sides

x^{2} + 2 x y - (x^{2} + 2 x y) = x^{2} + 2 x y - (x^{2} + 2 x y)

Simplify

0 = 0

Both sides are equal

True for all x

y, 2 x + 3 y = 3

42 = - 2 d + 6

x, 6 x - 10 y = 20

x, 8 x + 7 y = 51

f, f = {2 x - 1}

What is the answer to solvefor x,(x+y)^2=x^2+2xy+y^2 ?
The answer to solvefor x,(x+y)^2=x^2+2xy+y^2 is True for all x