What is factor x^4-2x^3+x^2-8x-12 ?

The solution to factor x^4-2x^3+x^2-8x-12 is (x+1)(x-3)(x^2+4)

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factor x^4-2x^3+x^2-8x-12

factor

x^{4} - 2 x^{3} + x^{2} - 8 x - 12

(x + 1) (x - 3) (x^{2} + 4)

Solution steps

x^{4} - 2 x^{3} + x^{2} - 8 x - 12

Use the rational root theorem

= (x + 1) \frac{x ^{4} - 2 x ^{3} + x ^{2} - 8 x - 12}{x + 1}

\frac{x ^{4} - 2 x ^{3} + x ^{2} - 8 x - 12}{x + 1} = x^{3} - 3 x^{2} + 4 x - 12

= (x + 1) (x^{3} - 3 x^{2} + 4 x - 12)

Factor

x^{3} - 3 x^{2} + 4 x - 12 : (x - 3) (x^{2} + 4)

= (x + 1) (x - 3) (x^{2} + 4)

(\frac{125}{128})^{5} \cdot 9838 \cdot 9 - 63333

x - 7 = - 1

6 b^{3} - 5 b^{2}

a^{2} - 29 ab + 100 b^{2}

(1 + 3 i)^{6}

What is factor x^4-2x^3+x^2-8x-12 ?
The solution to factor x^4-2x^3+x^2-8x-12 is (x+1)(x-3)(x^2+4)