What is the answer to solvefor u,s=ut+1/2 at^2 ?

The answer to solvefor u,s=ut+1/2 at^2 is u=(2s-t^2a)/(2t);\quad t\ne 0

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solvefor u,s=ut+1/2 at^2

solve for

u, s = u t + \frac{1}{2} a t^{2}

u = \frac{2 s - t ^{2} a}{2 t}; t \neq = 0

Solution steps

s = u t + \frac{1}{2} a t^{2}

Switch sides

u t + \frac{1}{2} a t^{2} = s

Move

\frac{1}{2} a t^{2}

to the right side

u t = s - \frac{1}{2} a t^{2}

Divide both sides by

t; t \neq = 0

u = \frac{2 s - t ^{2} a}{2 t}; t \neq = 0

y, 2 x + y = 9

lo g_{6} (25) - 6 lo g_{6} (5) + 4 lo g_{6} (30) = x

37 - 18 + 8 w = 67

10 + 2 z - 3 + z = 6 z - 3 - z

x, 2 x - y - 4 = 0

What is the answer to solvefor u,s=ut+1/2 at^2 ?
The answer to solvefor u,s=ut+1/2 at^2 is u=(2s-t^2a)/(2t);\quad t\ne 0