What is the answer to log_{10}(3)(2x-1)=2 ?

The answer to log_{10}(3)(2x-1)=2 is x=(2+log_{10}(3))/(2log_{10)(3)}

Solve for x: log_{10}(3)(2x-1)=2

The solution is x=(2+log_{10}(3))/(2log_{10)(3)}

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lo g_{10} (3) (2 x - 1) = 2

x = \frac{2 + lo g _{10} ( 3 )}{2 lo g _{10} ( 3 )}

Decimal Notation

x = 2.59590 \dots

Solution steps

lo g_{10} (3) (2 x - 1) = 2

Divide both sides by

lo g_{10} (3)

2 x - 1 = \frac{2}{lo g _{10} ( 3 )}

Move

1

to the right side

2 x = \frac{2}{lo g _{10} ( 3 )} + 1

Divide both sides by

2

x = \frac{2 + lo g _{10} ( 3 )}{2 lo g _{10} ( 3 )}

7 x - 4 = 2 x + 26

3 z + 6 = 17

P, A = P + I

x, 4 x - 8 y = 0

- 8 (9 x + 2) = - 12 - 8 x

What is the answer to log_{10}(3)(2x-1)=2 ?
The answer to log_{10}(3)(2x-1)=2 is x=(2+log_{10}(3))/(2log_{10)(3)}
Solve for x: log_{10}(3)(2x-1)=2
The solution is x=(2+log_{10}(3))/(2log_{10)(3)}