What is the answer to solvefor a,y=ax+bx^2 ?

The answer to solvefor a,y=ax+bx^2 is a=(y-bx^2)/x ;\quad x\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor a,y=ax+bx^2

solve for

a, y = a x + b x^{2}

a = \frac{y - b x ^{2}}{x}; x \neq = 0

Solution steps

y = a x + b x^{2}

Switch sides

a x + b x^{2} = y

Move

b x^{2}

to the right side

a x = y - b x^{2}

Divide both sides by

x; x \neq = 0

a = \frac{y - b x ^{2}}{x}; x \neq = 0

d = 1.6 + 5 d

3 + \frac{1}{3} x = 5

4 y - 3 = 12

2 + 4 (2 x - 1) = 6.25 x + 26

x, 3 y + \frac{x}{2} + 2 x y - 3 = 8

What is the answer to solvefor a,y=ax+bx^2 ?
The answer to solvefor a,y=ax+bx^2 is a=(y-bx^2)/x ;\quad x\ne 0