What is the answer to x^2+5=(x-1)(x-3) ?

The answer to x^2+5=(x-1)(x-3) is x=-1/2

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x^2+5=(x-1)(x-3)

x^{2} + 5 = (x - 1) (x - 3)

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

x^{2} + 5 = (x - 1) (x - 3)

Expand

(x - 1) (x - 3) : x^{2} - 4 x + 3

x^{2} + 5 = x^{2} - 4 x + 3

Move

5

to the right side

x^{2} = x^{2} - 4 x - 2

Subtract

x^{2} - 4 x

from both sides

x^{2} - (x^{2} - 4 x) = x^{2} - 4 x - 2 - (x^{2} - 4 x)

Simplify

4 x = - 2

Divide both sides by

4

x = - \frac{1}{2}

\frac{2 x}{5} - \frac{1}{5} = \frac{6 x}{5}

3 x - 5 = x + 7

x, - x + 5 y = 5

70 - 3 x = 4 x

- 6.24 = - 2.1 - 2.3 y

What is the answer to x^2+5=(x-1)(x-3) ?
The answer to x^2+5=(x-1)(x-3) is x=-1/2
Solve for x: x^2+5=(x-1)(x-3)
The solution is x=-1/2