What is factor x^4-x^3-7x^2+x+6 ?

The solution to factor x^4-x^3-7x^2+x+6 is (x-1)(x+1)(x+2)(x-3)

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factor x^4-x^3-7x^2+x+6

factor

x^{4} - x^{3} - 7 x^{2} + x + 6

(x - 1) (x + 1) (x + 2) (x - 3)

Solution steps

x^{4} - x^{3} - 7 x^{2} + x + 6

Use the rational root theorem

= (x - 1) \frac{x ^{4} - x ^{3} - 7 x ^{2} + x + 6}{x - 1}

\frac{x ^{4} - x ^{3} - 7 x ^{2} + x + 6}{x - 1} = x^{3} - 7 x - 6

= (x - 1) (x^{3} - 7 x - 6)

Factor

x^{3} - 7 x - 6 : (x + 1) (x + 2) (x - 3)

= (x - 1) (x + 1) (x + 2) (x - 3)

- 8 = a (- 8^{2} + 16 (- 8) + 60)

x^{2} - 15 = 0

z^{2} + 2 z

0.3 (10) - 18 (1 - e^{- \frac{10}{60}})

- 5 x^{3} - 10 x^{2} - 15 x

What is factor x^4-x^3-7x^2+x+6 ?
The solution to factor x^4-x^3-7x^2+x+6 is (x-1)(x+1)(x+2)(x-3)