What is the answer to 2/5 (10j-25+15j)-3/2 (6j-4)=-2j ?

The answer to 2/5 (10j-25+15j)-3/2 (6j-4)=-2j is j= 4/3

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2/5 (10j-25+15j)-3/2 (6j-4)=-2j

\frac{2}{5} (10 j - 25 + 15 j) - \frac{3}{2} (6 j - 4) = - 2 j

j = \frac{4}{3}

Decimal Notation

j = 1.33333 \dots

Solution steps

\frac{2}{5} (10 j - 25 + 15 j) - \frac{3}{2} (6 j - 4) = - 2 j

\frac{2}{5} (10 j - 25 + 15 j) = \frac{2 ( 25 j - 25 )}{5}

\frac{3}{2} (6 j - 4) = \frac{3 ( 6 j - 4 )}{2}

\frac{2 ( 25 j - 25 )}{5} - \frac{3 ( 6 j - 4 )}{2} = - 2 j

Multiply by LCM

100 (j - 1) - 30 (3 j - 2) = - 20 j

Expand

100 (j - 1) - 30 (3 j - 2) : 10 j - 40

10 j - 40 = - 20 j

Move

40

to the right side

10 j = - 20 j + 40

Move

20 j

to the left side

30 j = 40

Divide both sides by

30

j = \frac{4}{3}

5 x + 4 = 3 - 4 (x + 2)

x, 4 x + y = 20

3 (a + 10) = 27 a - (3 a - a)

\frac{1}{2} x - \frac{11}{4} = \frac{2}{3} x

x, 2 x = 2 y

What is the answer to 2/5 (10j-25+15j)-3/2 (6j-4)=-2j ?
The answer to 2/5 (10j-25+15j)-3/2 (6j-4)=-2j is j= 4/3
Solve for j: 2/5 (10j-25+15j)-3/2 (6j-4)=-2j
The solution is j= 4/3