What is the answer to (3-k)/8 =(2k+1)/5 ?

The answer to (3-k)/8 =(2k+1)/5 is k= 1/3

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(3-k)/8 =(2k+1)/5

\frac{3 - k}{8} = \frac{2 k + 1}{5}

k = \frac{1}{3}

Decimal Notation

k = 0.33333 \dots

Solution steps

\frac{3 - k}{8} = \frac{2 k + 1}{5}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(3 - k) \cdot 5 = 8 (2 k + 1)

Expand

(3 - k) \cdot 5 : 15 - 5 k

Expand

8 (2 k + 1) : 16 k + 8

15 - 5 k = 16 k + 8

Move

15

to the right side

- 5 k = 16 k - 7

Move

16 k

to the left side

- 21 k = - 7

Divide both sides by

- 21

k = \frac{1}{3}

7 (x - 1) - 2 (x + 1) = 4 x

- \frac{3}{10} t = \frac{1}{2} (\frac{1}{5} t - 14) + \frac{1}{10} t

x, x + 4 y = 10

7 - 3 x = 34

R, A = P + PRT

What is the answer to (3-k)/8 =(2k+1)/5 ?
The answer to (3-k)/8 =(2k+1)/5 is k= 1/3
Solve for k: (3-k)/8 =(2k+1)/5
The solution is k= 1/3