What is the answer to (x+2)+log_{2}(3)=log_{2}(27) ?

The answer to (x+2)+log_{2}(3)=log_{2}(27) is x=2log_{2}(3)-2

Solve for x: (x+2)+log_{2}(3)=log_{2}(27)

The solution is x=2log_{2}(3)-2

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(x + 2) + lo g_{2} (3) = lo g_{2} (27)

x = 2 lo g_{2} (3) - 2

Decimal Notation

x = 1.16992 \dots

Solution steps

(x + 2) + lo g_{2} (3) = lo g_{2} (27)

x + 2 + lo g_{2} (3) = lo g_{2} (27)

Move

2

to the right side

x + lo g_{2} (3) = 3 lo g_{2} (3) - 2

Move

lo g_{2} (3)

to the right side

x = 2 lo g_{2} (3) - 2

lo g_{10} (2) (8) = 3

2 + 34 x = x - 34

3 (2 x - 1) = - 2 (x + 3)

- 2 (8 m + 8) = - 16

2 x - 5 = 10

What is the answer to (x+2)+log_{2}(3)=log_{2}(27) ?
The answer to (x+2)+log_{2}(3)=log_{2}(27) is x=2log_{2}(3)-2
Solve for x: (x+2)+log_{2}(3)=log_{2}(27)
The solution is x=2log_{2}(3)-2