What are the solutions to the equation (-8Q^2+20Q+800)/(189)=0 ?

The solutions to the equation (-8Q^2+20Q+800)/(189)=0 are Q=-(5(sqrt(65)-1))/4 ,Q=(5(1+sqrt(65)))/4

Find the zeros of (-8Q^2+20Q+800)/(189)=0

The zeros of (-8Q^2+20Q+800)/(189)=0 are Q=-(5(sqrt(65)-1))/4 ,Q=(5(1+sqrt(65)))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{- 8 Q ^{2} + 20 Q + 800}{189} = 0

Q = - \frac{5 ( 65 - 1 )}{4}, Q = \frac{5 ( 1 + 65 )}{4}

Solution steps

\frac{- 8 Q ^{2} + 20 Q + 800}{189} = 0

Multiply both sides by

189

- 8 Q^{2} + 20 Q + 800 = 0

Solve with the quadratic formula

Q_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 8 ) \cdot 800}{2 ( - 8 )}

2 0^{2} - 4 (- 8) \cdot 800 = 2065

Q_{1, 2} = \frac{- 20 \pm 20 65}{2 ( - 8 )}

Separate the solutions

Q_{1} = \frac{- 20 + 20 65}{2 ( - 8 )}, Q_{2} = \frac{- 20 - 20 65}{2 ( - 8 )}

Q = \frac{- 20 + 20 65}{2 ( - 8 )} : - \frac{5 ( 65 - 1 )}{4}

Q = \frac{- 20 - 20 65}{2 ( - 8 )} : \frac{5 ( 1 + 65 )}{4}

The solutions to the quadratic equation are:

Q = - \frac{5 ( 65 - 1 )}{4}, Q = \frac{5 ( 1 + 65 )}{4}

- \frac{7}{8} x = - 5

11 - 2 ∣ x + 4 ∣ > 8

6 x^{5} - 48 x^{2}

3 (x + 4) > 21

4^{l o g_{2} (n)}

What are the solutions to the equation (-8Q^2+20Q+800)/(189)=0 ?
The solutions to the equation (-8Q^2+20Q+800)/(189)=0 are Q=-(5(sqrt(65)-1))/4 ,Q=(5(1+sqrt(65)))/4
Find the zeros of (-8Q^2+20Q+800)/(189)=0
The zeros of (-8Q^2+20Q+800)/(189)=0 are Q=-(5(sqrt(65)-1))/4 ,Q=(5(1+sqrt(65)))/4