What are the solutions to the equation x^2+10=-11x ?

The solutions to the equation x^2+10=-11x are x=-1,x=-10

Find the zeros of x^2+10=-11x

The zeros of x^2+10=-11x are x=-1,x=-10

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x^{2} + 10 = - 11 x

x = - 1, x = - 10

Solution steps

x^{2} + 10 = - 11 x

Move

11 x

to the left side

x^{2} + 10 + 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 11 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 10 = 9

x_{1, 2} = \frac{- 11 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 9}{2 \cdot 1}, x_{2} = \frac{- 11 - 9}{2 \cdot 1}

x = \frac{- 11 + 9}{2 \cdot 1} : - 1

x = \frac{- 11 - 9}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 1, x = - 10

x^{2} = 7 x + 18

6 x^{2} - 6 = 0

\frac{t}{5} - 13 = - 3

x^{2} - 2 x + 3 x - 6

\frac{4}{4} - \frac{3}{4}

What are the solutions to the equation x^2+10=-11x ?
The solutions to the equation x^2+10=-11x are x=-1,x=-10
Find the zeros of x^2+10=-11x
The zeros of x^2+10=-11x are x=-1,x=-10