What are the solutions to the equation (y+4)(3y-5)=0 ?

The solutions to the equation (y+4)(3y-5)=0 are y=-4,y= 5/3

Find the zeros of (y+4)(3y-5)=0

The zeros of (y+4)(3y-5)=0 are y=-4,y= 5/3

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(y + 4) (3 y - 5) = 0

y = - 4, y = \frac{5}{3}

Decimal Notation

y = - 4, y = 1.66666 \dots

Solution steps

(y + 4) (3 y - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y + 4 = 0 or 3 y - 5 = 0

Solve

y + 4 = 0 : y = - 4

Solve

3 y - 5 = 0 : y = \frac{5}{3}

The solutions to the quadratic equation are:

y = - 4, y = \frac{5}{3}

6 x^{2} - 7 x - 20

3 y^{2} + 23 y + 30

- x^{2} - 8 x - 19 \leq - 4

6 p = 0.6 (5 p + 15)

(64 x^{9} y^{24})^{- \frac{5}{3}}

What are the solutions to the equation (y+4)(3y-5)=0 ?
The solutions to the equation (y+4)(3y-5)=0 are y=-4,y= 5/3
Find the zeros of (y+4)(3y-5)=0
The zeros of (y+4)(3y-5)=0 are y=-4,y= 5/3