What is the answer to solvefor f,f=(x^3+y/2)^{2/3} ?

The answer to solvefor f,f=(x^3+y/2)^{2/3} is f=((2x^3+y)/2)^{2/3}

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solvefor f,f=(x^3+y/2)^{2/3}

solve for

f, f = (x^{3} + \frac{y}{2})^{\frac{2}{3}}

f = (\frac{2 x ^{3} + y}{2})^{\frac{2}{3}}

Solution steps

f = (x^{3} + \frac{y}{2})^{\frac{2}{3}}

Join

x^{3} + \frac{y}{2} : \frac{2 x ^{3} + y}{2}

f = (\frac{2 x ^{3} + y}{2})^{\frac{2}{3}}

a, a - f = q

x, 7 x + 8 y = 29

\frac{7 x}{2} - 4 = 5

x, 2 x + 3 y - 1 = 0

x, 2 x + 3 y - 7 = 0

What is the answer to solvefor f,f=(x^3+y/2)^{2/3} ?
The answer to solvefor f,f=(x^3+y/2)^{2/3} is f=((2x^3+y)/2)^{2/3}