What are the solutions to the equation x^2-10x+22=-2 ?

The solutions to the equation x^2-10x+22=-2 are x=6,x=4

Find the zeros of x^2-10x+22=-2

The zeros of x^2-10x+22=-2 are x=6,x=4

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x^{2} - 10 x + 22 = - 2

x = 6, x = 4

Solution steps

x^{2} - 10 x + 22 = - 2

Move

2

to the left side

x^{2} - 10 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

x_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

x = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 6, x = 4

\frac{14 x ^{4} y ^{7}}{6 x ^{5} y ^{4}}

- 6 \cdot 2

\frac{1 - \frac{3}{4}}{\frac{7}{12}}

\frac{1}{x - 2} - \frac{2}{x - 1} < 0

6 x^{2} - 6 x - 36 = 84

What are the solutions to the equation x^2-10x+22=-2 ?
The solutions to the equation x^2-10x+22=-2 are x=6,x=4
Find the zeros of x^2-10x+22=-2
The zeros of x^2-10x+22=-2 are x=6,x=4