What is the answer to solvefor f,(f/g)(x)=(x^2-1)/(x+1) ?

The answer to solvefor f,(f/g)(x)=(x^2-1)/(x+1) is f=((x-1)g)/x ;\quad x\ne 0,g\ne 0

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solvefor f,(f/g)(x)=(x^2-1)/(x+1)

solve for

f, (\frac{f}{g}) (x) = \frac{x ^{2} - 1}{x + 1}

f = \frac{( x - 1 ) g}{x}; x \neq = 0, g \neq = 0

Solution steps

(\frac{f}{g}) (x) = \frac{x ^{2} - 1}{x + 1}

Divide both sides by

x; x \neq = 0

\frac{f}{g} = \frac{x - 1}{x}; x \neq = 0

Multiply both sides by

g

f = \frac{( x - 1 ) g}{x}; x \neq = 0, g \neq = 0

a, u = \frac{ak}{b}

x, 4 y = 3 x - 2

3 x + 2 = 26

y, x - 2 y = - 2

x, \frac{x - 4}{y + 2} = 5

What is the answer to solvefor f,(f/g)(x)=(x^2-1)/(x+1) ?
The answer to solvefor f,(f/g)(x)=(x^2-1)/(x+1) is f=((x-1)g)/x ;\quad x\ne 0,g\ne 0