What is the answer to solvefor T,T(n)=T(sqrt(n))+1 ?

The answer to solvefor T,T(n)=T(sqrt(n))+1 is T=(sqrt(n)+1)/(sqrt(n)(n-1));\quad n\ne 1,n\ne 0

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solvefor T,T(n)=T(sqrt(n))+1

solve for

T, T (n) = T (n) + 1

T = \frac{n + 1}{n ( n - 1 )}; n \neq = 1, n \neq = 0

Solution steps

T (n) = T (n) + 1

T (n) = n T + 1

Expand

T (n) : n T

n T = n T + 1

Move

n T

to the left side

n T - n T = 1

Factor

n T - n T : T (n - n)

T (n - n) = 1

Divide both sides by

n - n; n \neq = 1, n \neq = 0

T = \frac{n + 1}{n ( n - 1 )}; n \neq = 1, n \neq = 0

f, f (x + h) = - 2 x + 1

a, D = G a + 3 h^{3} a

\frac{( x - 5 )}{3} = 21

6^{2} + 8^{2} = 1 0^{2}

25 + \frac{7}{9} b = 74

What is the answer to solvefor T,T(n)=T(sqrt(n))+1 ?
The answer to solvefor T,T(n)=T(sqrt(n))+1 is T=(sqrt(n)+1)/(sqrt(n)(n-1));\quad n\ne 1,n\ne 0