What is the answer to solvefor x,yz+xln(y)=z^2 ?

The answer to solvefor x,yz+xln(y)=z^2 is x=(z^2-yz)/(ln(y));\quad y\ne 1

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solvefor x,yz+xln(y)=z^2

solve for

x, yz + x ln (y) = z^{2}

x = \frac{z ^{2} - yz}{ln ( y )}; y \neq = 1

Solution steps

yz + x ln (y) = z^{2}

Move

yz

to the right side

x ln (y) = z^{2} - yz

Divide both sides by

ln (y); y \neq = 1

x = \frac{z ^{2} - yz}{ln ( y )}; y \neq = 1

\frac{x - 9}{6} = \frac{2 x - 4}{5}

\frac{1 - 2 x}{9} = 1 - \frac{x + 4}{6}

2 (2 + 4 x) = 3 + 12 x

x (x^{2} - 1) = 3 + x^{3}

6 x - 10 = 0

What is the answer to solvefor x,yz+xln(y)=z^2 ?
The answer to solvefor x,yz+xln(y)=z^2 is x=(z^2-yz)/(ln(y));\quad y\ne 1