What are the solutions to the equation 3(x^2-9)+8=2 ?

The solutions to the equation 3(x^2-9)+8=2 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 3(x^2-9)+8=2

The zeros of 3(x^2-9)+8=2 are x=sqrt(7),x=-sqrt(7)

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3 (x^{2} - 9) + 8 = 2

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

3 (x^{2} - 9) + 8 = 2

Move

8

to the right side

3 (x^{2} - 9) = - 6

Divide both sides by

3

x^{2} - 9 = - 2

Move

9

to the right side

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

x^{4} + 4 x^{3} - x^{2} - 4 x

x^{2} - 2 x - 16 = - 9

5 = (1 + \frac{200}{66.5}) 1.25 + (200000 \cdot x)

5 m^{2} - m - 6 = 0

(- 27)^{\frac{4}{3}}

What are the solutions to the equation 3(x^2-9)+8=2 ?
The solutions to the equation 3(x^2-9)+8=2 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 3(x^2-9)+8=2
The zeros of 3(x^2-9)+8=2 are x=sqrt(7),x=-sqrt(7)