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Popular >

solvefor b,z=2c+2+4b

Solution

solve for

b, z = 2 c + 2 + 4 b

Solution

b = \frac{z - 2 c - 2}{4}

Solution steps

z = 2 c + 2 + 4 b

Switch sides

2 c + 2 + 4 b = z

Move

2 c

to the right side

2 + 4 b = z - 2 c

Move

2

to the right side

4 b = z - 2 c - 2

Divide both sides by

4

b = \frac{z - 2 c - 2}{4}

Popular Examples

x^2-{3x+[x(x+1)+4(x^2-1)-4x^2]}=0

x^{2} - {3 x + [x (x + 1) + 4 (x^{2} - 1) - 4 x^{2}]} = 0

l + 15.2 = - 4.5

(x+3)/4-(x-4)/9 = 1/2-(x+1)/4+(2x+1)/9

\frac{x + 3}{4} - \frac{x - 4}{9} = \frac{1}{2} - \frac{x + 1}{4} + \frac{2 x + 1}{9}

solvefor x,2x-3y-12=0 solve for

x, 2 x - 3 y - 12 = 0

(5r+7)/3 =3-r/6

\frac{5 r + 7}{3} = 3 - \frac{r}{6}

Frequently Asked Questions (FAQ)

What is the answer to solvefor b,z=2c+2+4b ?
The answer to solvefor b,z=2c+2+4b is b=(z-2c-2)/4