What is the answer to a= 1/2 h(b^1+b^2) ?

The answer to a= 1/2 h(b^1+b^2) is h=(2a)/(b+b^2);\quad b\ne 0,b\ne-1

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a= 1/2 h(b^1+b^2)

a = \frac{1}{2} h (b^{1} + b^{2})

h = \frac{2 a}{b + b ^{2}}; b \neq = 0, b \neq = - 1

Solution steps

a = \frac{1}{2} h (b^{1} + b^{2})

Switch sides

\frac{1}{2} h (b^{1} + b^{2}) = a

Multiply both sides by

2

h (b + b^{2}) = 2 a

Divide both sides by

b + b^{2}; b \neq = 0, b \neq = - 1

h = \frac{2 a}{b + b ^{2}}; b \neq = 0, b \neq = - 1

- 1 + x = - 5

y = - 1 + 3

y, x = y + 5

5 x - 3 = 3 x + 1

x, y - 3 = - 3 x

What is the answer to a= 1/2 h(b^1+b^2) ?
The answer to a= 1/2 h(b^1+b^2) is h=(2a)/(b+b^2);\quad b\ne 0,b\ne-1