What are the solutions to the equation 2x^2+11x-1=0 ?

The solutions to the equation 2x^2+11x-1=0 are x=(-11+sqrt(129))/4 ,x=(-11-sqrt(129))/4

Find the zeros of 2x^2+11x-1=0

The zeros of 2x^2+11x-1=0 are x=(-11+sqrt(129))/4 ,x=(-11-sqrt(129))/4

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2 x^{2} + 11 x - 1 = 0

x = \frac{- 11 + 129}{4}, x = \frac{- 11 - 129}{4}

Decimal Notation

x = 0.08945 \dots, x = - 5.58945 \dots

Solution steps

2 x^{2} + 11 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 (- 1) = 129

x_{1, 2} = \frac{- 11 \pm 129}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 11 + 129}{2 \cdot 2}, x_{2} = \frac{- 11 - 129}{2 \cdot 2}

x = \frac{- 11 + 129}{2 \cdot 2} : \frac{- 11 + 129}{4}

x = \frac{- 11 - 129}{2 \cdot 2} : \frac{- 11 - 129}{4}

The solutions to the quadratic equation are:

x = \frac{- 11 + 129}{4}, x = \frac{- 11 - 129}{4}

x^{2} - 169 < 0

25000 = 84 x

- 120 m^{2} - 190 m - 50

lo g_{25} (625)

16 x^{3} + 54 y^{6}

What are the solutions to the equation 2x^2+11x-1=0 ?
The solutions to the equation 2x^2+11x-1=0 are x=(-11+sqrt(129))/4 ,x=(-11-sqrt(129))/4
Find the zeros of 2x^2+11x-1=0
The zeros of 2x^2+11x-1=0 are x=(-11+sqrt(129))/4 ,x=(-11-sqrt(129))/4