What is the answer to (2-3x)^2-(3x-1)(3x+1)=2 ?

The answer to (2-3x)^2-(3x-1)(3x+1)=2 is x= 1/4

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(2-3x)^2-(3x-1)(3x+1)=2

(2 - 3 x)^{2} - (3 x - 1) (3 x + 1) = 2

x = \frac{1}{4}

Solution steps

(2 - 3 x)^{2} - (3 x - 1) (3 x + 1) = 2

Expand

(2 - 3 x)^{2} - (3 x - 1) (3 x + 1) : - 12 x + 5

- 12 x + 5 = 2

Move

5

to the right side

- 12 x = - 3

Divide both sides by

- 12

x = \frac{1}{4}

- 6 x = 24

3 \cdot (x + 1) = 15

\frac{2 x}{3} - 8 = \frac{x}{6} + \frac{3}{2}

1.5 (w + 3) = 0.6 w

B, \frac{B}{5 H} = F + G

What is the answer to (2-3x)^2-(3x-1)(3x+1)=2 ?
The answer to (2-3x)^2-(3x-1)(3x+1)=2 is x= 1/4
Solve for x: (2-3x)^2-(3x-1)(3x+1)=2
The solution is x= 1/4