What are the solutions to the equation x^2+3x=6 ?

The solutions to the equation x^2+3x=6 are x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2

Find the zeros of x^2+3x=6

The zeros of x^2+3x=6 are x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2

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x^{2} + 3 x = 6

x = \frac{- 3 + 33}{2}, x = \frac{- 3 - 33}{2}

Solution steps

x^{2} + 3 x = 6

Move

6

to the left side

x^{2} + 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 6) = 33

x_{1, 2} = \frac{- 3 \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 33}{2 \cdot 1}, x_{2} = \frac{- 3 - 33}{2 \cdot 1}

x = \frac{- 3 + 33}{2 \cdot 1} : \frac{- 3 + 33}{2}

x = \frac{- 3 - 33}{2 \cdot 1} : \frac{- 3 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 33}{2}, x = \frac{- 3 - 33}{2}

(4)^{\frac{2}{3}}

6 x^{2} + 4 = 25 x

2 (x^{2} - 2) < 3 (x - 3) - x^{2}

x^{10} - y^{10}

242 h^{2} - 200

What are the solutions to the equation x^2+3x=6 ?
The solutions to the equation x^2+3x=6 are x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2
Find the zeros of x^2+3x=6
The zeros of x^2+3x=6 are x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2