What are the solutions to the equation -2x^2-9x=-4 ?

The solutions to the equation -2x^2-9x=-4 are x=-(9+sqrt(113))/4 ,x=(sqrt(113)-9)/4

Find the zeros of -2x^2-9x=-4

The zeros of -2x^2-9x=-4 are x=-(9+sqrt(113))/4 ,x=(sqrt(113)-9)/4

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- 2 x^{2} - 9 x = - 4

x = - \frac{9 + 113}{4}, x = \frac{113 - 9}{4}

Decimal Notation

x = - 4.90753 \dots, x = 0.40753 \dots

Solution steps

- 2 x^{2} - 9 x = - 4

Move

4

to the left side

- 2 x^{2} - 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 2 ) \cdot 4}{2 ( - 2 )}

(- 9)^{2} - 4 (- 2) \cdot 4 = 113

x_{1, 2} = \frac{- ( - 9 ) \pm 113}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 113}{2 ( - 2 )}, x_{2} = \frac{- ( - 9 ) - 113}{2 ( - 2 )}

x = \frac{- ( - 9 ) + 113}{2 ( - 2 )} : - \frac{9 + 113}{4}

x = \frac{- ( - 9 ) - 113}{2 ( - 2 )} : \frac{113 - 9}{4}

The solutions to the quadratic equation are:

x = - \frac{9 + 113}{4}, x = \frac{113 - 9}{4}

\frac{1.1 - 2}{( 1.1 - 1 ) ^{2}}

2 n^{2} + 8 n

4 - 3 (3 - n) \leq 3 (2 - 5 n)

\frac{4 x + 8}{x ^{2} - 3 x + 2} > 0

3 ∣ 2 x + 1 ∣ + 4 = 25

What are the solutions to the equation -2x^2-9x=-4 ?
The solutions to the equation -2x^2-9x=-4 are x=-(9+sqrt(113))/4 ,x=(sqrt(113)-9)/4
Find the zeros of -2x^2-9x=-4
The zeros of -2x^2-9x=-4 are x=-(9+sqrt(113))/4 ,x=(sqrt(113)-9)/4