What is the answer to log_{10}(2)(x)+log_{10}(2)(x-3)=2 ?

The answer to log_{10}(2)(x)+log_{10}(2)(x-3)=2 is x=(2+3log_{10}(2))/(2log_{10)(2)}

Solve for x: log_{10}(2)(x)+log_{10}(2)(x-3)=2

The solution is x=(2+3log_{10}(2))/(2log_{10)(2)}

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lo g_{10} (2) (x) + lo g_{10} (2) (x - 3) = 2

x = \frac{2 + 3 lo g _{10} ( 2 )}{2 lo g _{10} ( 2 )}

Decimal Notation

x = 4.82192 \dots

Solution steps

lo g_{10} (2) (x) + lo g_{10} (2) (x - 3) = 2

lo g_{10} (2) x + lo g_{10} (2) (x - 3) = 2

Expand

lo g_{10} (2) (x - 3) : lo g_{10} (2) x - 3 lo g_{10} (2)

lo g_{10} (2) x + lo g_{10} (2) x - 3 lo g_{10} (2) = 2

Add similar elements:

lo g_{10} (2) x + lo g_{10} (2) x = 2 lo g_{10} (2) x

2 lo g_{10} (2) x - 3 lo g_{10} (2) = 2

Move

3 lo g_{10} (2)

to the right side

2 lo g_{10} (2) x = 2 + 3 lo g_{10} (2)

Divide both sides by

2 lo g_{10} (2)

x = \frac{2 + 3 lo g _{10} ( 2 )}{2 lo g _{10} ( 2 )}

35 h + 25 = 40 h

3 x + 4 = 5 x - 8

6 (2 x - 5) + 2 = 20

(2 x + 1) = x + 4

7 + 4 t = 5 t + 17

What is the answer to log_{10}(2)(x)+log_{10}(2)(x-3)=2 ?
The answer to log_{10}(2)(x)+log_{10}(2)(x-3)=2 is x=(2+3log_{10}(2))/(2log_{10)(2)}
Solve for x: log_{10}(2)(x)+log_{10}(2)(x-3)=2
The solution is x=(2+3log_{10}(2))/(2log_{10)(2)}