What is the answer to solvefor x,y(x-y)+2z(x-3z)=5yz ?

The answer to solvefor x,y(x-y)+2z(x-3z)=5yz is x=y+3z;\quad y\ne-2z

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solvefor x,y(x-y)+2z(x-3z)=5yz

solve for

x, y (x - y) + 2 z (x - 3 z) = 5 yz

x = y + 3 z; y \neq = - 2 z

Solution steps

y (x - y) + 2 z (x - 3 z) = 5 yz

Expand

y (x - y) : x y - y^{2}

x y - y^{2} + 2 z (x - 3 z) = 5 yz

Expand

2 z (x - 3 z) : 2 x z - 6 z^{2}

x y - y^{2} + 2 x z - 6 z^{2} = 5 yz

Move

y^{2}

to the right side

x y + 2 x z - 6 z^{2} = 5 yz + y^{2}

Move

6 z^{2}

to the right side

x y + 2 x z = 5 yz + y^{2} + 6 z^{2}

Factor

x y + 2 x z : x (y + 2 z)

x (y + 2 z) = 5 yz + y^{2} + 6 z^{2}

Divide both sides by

y + 2 z; y \neq = - 2 z

x = y + 3 z; y \neq = - 2 z

- \frac{x}{1.6} - 1.8 = - 3.3

- x - 4 x = - \frac{2}{3} x + 2

3 x + 4 = 7 x - (x + 17)

x, - 3 x + 6 y = 18

\frac{1}{2} (\frac{2}{3} x + 10) = \frac{3}{5} x + 1

What is the answer to solvefor x,y(x-y)+2z(x-3z)=5yz ?
The answer to solvefor x,y(x-y)+2z(x-3z)=5yz is x=y+3z;\quad y\ne-2z