What is the answer to solvefor x,132+12x(3)-z=42+35z+122 ?

The answer to solvefor x,132+12x(3)-z=42+35z+122 is x=(9z+8)/9

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solvefor x,132+12x(3)-z=42+35z+122

solve for

x, 132 + 12 x (3) - z = 42 + 35 z + 122

x = \frac{9 z + 8}{9}

Solution steps

132 + 12 x (3) - z = 42 + 35 z + 122

Remove parentheses:

(a) = a

132 + 12 x \cdot 3 - z = 42 + 35 z + 122

Multiply the numbers:

12 \cdot 3 = 36

132 + 36 x - z = 42 + 35 z + 122

Add the numbers:

42 + 122 = 164

132 + 36 x - z = 35 z + 164

Move

z

to the right side

132 + 36 x = 36 z + 164

Move

132

to the right side

36 x = 36 z + 32

Divide both sides by

36

x = \frac{9 z + 8}{9}

3 x + 4 (- 2 x + 1) = 3 (x - 5) + 2 (2 x - 7) - 3

\frac{2}{3} - 6 x = \frac{3 x}{2} - 6

\frac{5 x - 1}{3} = 3 x + 1

x, 2 x + 2 y = 18

2 x - 8 = 14

What is the answer to solvefor x,132+12x(3)-z=42+35z+122 ?
The answer to solvefor x,132+12x(3)-z=42+35z+122 is x=(9z+8)/9