What is the answer to x^2-1=(x+1)(x-1) ?

The answer to x^2-1=(x+1)(x-1) is True for all x

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x^2-1=(x+1)(x-1)

x^{2} - 1 = (x + 1) (x - 1)

True for all x

Solution steps

x^{2} - 1 = (x + 1) (x - 1)

Expand

(x + 1) (x - 1) : x^{2} - 1

x^{2} - 1 = x^{2} - 1

Move

1

to the right side

x^{2} = x^{2}

Move

x^{2}

to the left side

0 = 0

Both sides are equal

True for all x

x - 2 = 12

3 g + 5 = 17

- 3.2 \cdot 1 0^{- 8} = x \cdot 1.6 \cdot 1 0^{- 19}

\frac{n}{- 3} = 4

\frac{1}{2} x = 0

What is the answer to x^2-1=(x+1)(x-1) ?
The answer to x^2-1=(x+1)(x-1) is True for all x
Solve for x: x^2-1=(x+1)(x-1)
The solution is True for all x