What is the answer to solvefor b,bc=ac+ab ?

The answer to solvefor b,bc=ac+ab is b=(ac)/(c-a);\quad c\ne a

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solvefor b,bc=ac+ab

solve for

b, b c = a c + ab

b = \frac{a c}{c - a}; c \neq = a

Solution steps

b c = a c + ab

Move

ab

to the left side

b c - ab = a c

Factor

b c - ab : b (c - a)

b (c - a) = a c

Divide both sides by

c - a; c \neq = a

b = \frac{a c}{c - a}; c \neq = a

a, z = a + bi

x, 2 x + 7 y = 9

x, x + 5 y = 7

8 x = 8

y = \frac{1}{0}

What is the answer to solvefor b,bc=ac+ab ?
The answer to solvefor b,bc=ac+ab is b=(ac)/(c-a);\quad c\ne a