What are the solutions to the equation 4x^2+2x+4=0 ?

The solutions to the equation 4x^2+2x+4=0 are x=-1/4+i(sqrt(15))/4 ,x=-1/4-i(sqrt(15))/4

Find the zeros of 4x^2+2x+4=0

The zeros of 4x^2+2x+4=0 are x=-1/4+i(sqrt(15))/4 ,x=-1/4-i(sqrt(15))/4

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4 x^{2} + 2 x + 4 = 0

x = - \frac{1}{4} + i \frac{15}{4}, x = - \frac{1}{4} - i \frac{15}{4}

Solution steps

4 x^{2} + 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

Simplify

2^{2} - 4 \cdot 4 \cdot 4 : 215 i

x_{1, 2} = \frac{- 2 \pm 2 15 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 2 + 2 15 i}{2 \cdot 4}, x_{2} = \frac{- 2 - 2 15 i}{2 \cdot 4}

x = \frac{- 2 + 2 15 i}{2 \cdot 4} : - \frac{1}{4} + i \frac{15}{4}

x = \frac{- 2 - 2 15 i}{2 \cdot 4} : - \frac{1}{4} - i \frac{15}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{15}{4}, x = - \frac{1}{4} - i \frac{15}{4}

∣ 5 x - 4 ∣ + 2 \geq 9

- \frac{1 ( 2 ( - 1 ) + 1 )}{- 1 ( - 1 + 2 ( 1 ) )}

26 = 7 (g - 9) + 12

16 x^{2} + 72 x + 81 = 0

x^{2} - 6 x + 9 = 0

What are the solutions to the equation 4x^2+2x+4=0 ?
The solutions to the equation 4x^2+2x+4=0 are x=-1/4+i(sqrt(15))/4 ,x=-1/4-i(sqrt(15))/4
Find the zeros of 4x^2+2x+4=0
The zeros of 4x^2+2x+4=0 are x=-1/4+i(sqrt(15))/4 ,x=-1/4-i(sqrt(15))/4