What is the answer to solvefor x,1-2xy+y^2=0 ?

The answer to solvefor x,1-2xy+y^2=0 is x=-(-y^2-1)/(2y);\quad y\ne 0

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solvefor x,1-2xy+y^2=0

solve for

x, 1 - 2 x y + y^{2} = 0

x = - \frac{- y ^{2} - 1}{2 y}; y \neq = 0

Solution steps

1 - 2 x y + y^{2} = 0

Move

y^{2}

to the right side

1 - 2 x y = - y^{2}

Move

1

to the right side

- 2 x y = - y^{2} - 1

Divide both sides by

- 2 y; y \neq = 0

x = - \frac{- y ^{2} - 1}{2 y}; y \neq = 0

\frac{2}{3} (\frac{1}{2} s + 6) - 4 (\frac{3}{2} - \frac{3}{2} s) = 6 s

x, - 3 x + y = - 1

x, - 3 x + y = - 8

y, 2 x - 4 y = 12

s, h (s) = 3 + \frac{2}{3} s

What is the answer to solvefor x,1-2xy+y^2=0 ?
The answer to solvefor x,1-2xy+y^2=0 is x=-(-y^2-1)/(2y);\quad y\ne 0