What is the answer to (x+1)/8-(x-1)/6+(x+3)/5 =2 ?

The answer to (x+1)/8-(x-1)/6+(x+3)/5 =2 is x=7

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(x+1)/8-(x-1)/6+(x+3)/5 =2

\frac{x + 1}{8} - \frac{x - 1}{6} + \frac{x + 3}{5} = 2

x = 7

Solution steps

\frac{x + 1}{8} - \frac{x - 1}{6} + \frac{x + 3}{5} = 2

Multiply by LCM

15 (x + 1) - 20 (x - 1) + 24 (x + 3) = 240

Expand

15 (x + 1) - 20 (x - 1) + 24 (x + 3) : 19 x + 107

19 x + 107 = 240

Move

107

to the right side

19 x = 133

Divide both sides by

19

x = 7

a, lo g_{81} (3) = \frac{a}{b}

\frac{6}{4} a + \frac{2}{10} = 4

- 5 y + 6 = - 12 y + 62

2 (x + 4) - 1 = 2 x + 7

x, (x + 5) \frac{2}{9} - (y + 1) \frac{2}{49} = 1

What is the answer to (x+1)/8-(x-1)/6+(x+3)/5 =2 ?
The answer to (x+1)/8-(x-1)/6+(x+3)/5 =2 is x=7
Solve for x: (x+1)/8-(x-1)/6+(x+3)/5 =2
The solution is x=7