What is the answer to solvefor d,4hd=3f-g^3 ?

The answer to solvefor d,4hd=3f-g^3 is d=(3f-g^3)/(4h);\quad h\ne 0

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solvefor d,4hd=3f-g^3

solve for

d, 4 h d = 3 f - g^{3}

d = \frac{3 f - g ^{3}}{4 h}; h \neq = 0

Solution steps

4 h d = 3 f - g^{3}

Divide both sides by

4 h; h \neq = 0

d = \frac{3 f - g ^{3}}{4 h}; h \neq = 0

\frac{2 x}{3} + \frac{16}{3} = \frac{4 x}{2}

\frac{9}{4} (8 x - 4 + \frac{4}{3} x) = 2 - x

4 y^{2} + 7 y = 10 + (2 y - 3)^{2}

y, x - y = 7

\frac{( 5 x + 6 )}{2} = 3 - (4 x + 12)

What is the answer to solvefor d,4hd=3f-g^3 ?
The answer to solvefor d,4hd=3f-g^3 is d=(3f-g^3)/(4h);\quad h\ne 0