What is the answer to (3x+5)*(2x+4)=6x^2-2 ?

The answer to (3x+5)*(2x+4)=6x^2-2 is x=-1

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(3x+5)*(2x+4)=6x^2-2

(3 x + 5) \cdot (2 x + 4) = 6 x^{2} - 2

x = - 1

Solution steps

(3 x + 5) (2 x + 4) = 6 x^{2} - 2

Expand

(3 x + 5) (2 x + 4) : 6 x^{2} + 22 x + 20

6 x^{2} + 22 x + 20 = 6 x^{2} - 2

Move

20

to the right side

6 x^{2} + 22 x = 6 x^{2} - 22

Move

6 x^{2}

to the left side

22 x = - 22

Divide both sides by

22

x = - 1

6 x - 3 = 2 x + 5

x, x + y + z = 7

T, T (n) = \frac{5 n + 11}{n}

31 = \frac{4}{5} c - 1

x, x - 4 y = 32

What is the answer to (3x+5)*(2x+4)=6x^2-2 ?
The answer to (3x+5)*(2x+4)=6x^2-2 is x=-1
Solve for x: (3x+5)*(2x+4)=6x^2-2
The solution is x=-1