What are the solutions to the equation -(4*x-1)+8*x-16*x^2=1 ?

The solutions to the equation -(4*x-1)+8*x-16*x^2=1 are x=0,x= 1/4

Find the zeros of -(4*x-1)+8*x-16*x^2=1

The zeros of -(4*x-1)+8*x-16*x^2=1 are x=0,x= 1/4

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- (4 \cdot x - 1) + 8 \cdot x - 16 \cdot x^{2} = 1

x = 0, x = \frac{1}{4}

Decimal Notation

x = 0, x = 0.25

Solution steps

- (4 x - 1) + 8 x - 16 x^{2} = 1

Expand

- (4 x - 1) + 8 x - 16 x^{2} : - 16 x^{2} + 4 x + 1

- 16 x^{2} + 4 x + 1 = 1

Move

1

to the left side

- 16 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

4^{2} - 4 (- 16) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 16 )}, x_{2} = \frac{- 4 - 4}{2 ( - 16 )}

x = \frac{- 4 + 4}{2 ( - 16 )} : 0

x = \frac{- 4 - 4}{2 ( - 16 )} : \frac{1}{4}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{4}

9 - 7 ∣ 3 + 2 r ∣ \leq - 26

2 x + 3 \geq 7

y^{2} + 16 y + 28

\frac{4}{5} x - \frac{2}{5} = 7

What are the solutions to the equation -(4*x-1)+8*x-16*x^2=1 ?
The solutions to the equation -(4*x-1)+8*x-16*x^2=1 are x=0,x= 1/4
Find the zeros of -(4*x-1)+8*x-16*x^2=1
The zeros of -(4*x-1)+8*x-16*x^2=1 are x=0,x= 1/4