What is the answer to solvefor d,2m^3dm+3mn^3dn=n^3dm ?

The answer to solvefor d,2m^3dm+3mn^3dn=n^3dm is d=0

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solvefor d,2m^3dm+3mn^3dn=n^3dm

solve for

d, 2 m^{3} d m + 3 m n^{3} d n = n^{3} d m

d = 0

Solution steps

2 m^{3} d m + 3 m n^{3} d n = n^{3} d m

Simplify

2 m^{3} d m + 3 m n^{3} d n : 2 m^{4} d + 3 m n^{4} d

2 m^{4} d + 3 m n^{4} d = n^{3} d m

Move

n^{3} d m

to the left side

2 m^{4} d + 3 m n^{4} d - n^{3} d m = 0

Factor

2 m^{4} d + 3 m n^{4} d - n^{3} d m : m d (2 m^{3} + 3 n^{4} - n^{3})

m d (2 m^{3} + 3 n^{4} - n^{3}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

d = 0

\frac{x + 2}{6} = \frac{x - 4}{7}

f = 3 (2)^{- 1}

- \frac{6}{7} - \frac{2}{3} c = \frac{1}{7}

\frac{x + 3}{4} = 12

\frac{8}{3} x - 2 = \frac{4}{5} (x + 1)

What is the answer to solvefor d,2m^3dm+3mn^3dn=n^3dm ?
The answer to solvefor d,2m^3dm+3mn^3dn=n^3dm is d=0