What is the answer to 2amx-4a=5mx+m-2ax ?

The answer to 2amx-4a=5mx+m-2ax is x=(m+4a)/(2am-5m+2a);\quad a\ne (5m)/(2(m+1))

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2amx-4a=5mx+m-2ax

2 am x - 4 a = 5 m x + m - 2 a x

x = \frac{m + 4 a}{2 am - 5 m + 2 a}; a \neq = \frac{5 m}{2 ( m + 1 )}

Solution steps

2 am x - 4 a = 5 m x + m - 2 a x

Move

4 a

to the right side

2 am x = 5 m x + m - 2 a x + 4 a

Subtract

5 m x - 2 a x

from both sides

2 am x - (5 m x - 2 a x) = 5 m x + m - 2 a x + 4 a - (5 m x - 2 a x)

Simplify

2 am x - 5 m x + 2 a x = m + 4 a

Factor

2 am x - 5 m x + 2 a x : x (2 am - 5 m + 2 a)

x (2 am - 5 m + 2 a) = m + 4 a

Divide both sides by

2 am - 5 m + 2 a; a \neq = \frac{5 m}{2 ( m + 1 )}

x = \frac{m + 4 a}{2 am - 5 m + 2 a}; a \neq = \frac{5 m}{2 ( m + 1 )}

3 x - 66 + 8 x = - 7 x + 13 + x + 23

x, 5 x = y - 4

11 x - 3 = 4 x - 31

1 + y = 1

x, - 1.5 y = 4.5 x - 9

What is the answer to 2amx-4a=5mx+m-2ax ?
The answer to 2amx-4a=5mx+m-2ax is x=(m+4a)/(2am-5m+2a);\quad a\ne (5m)/(2(m+1))