What is the answer to (x-3}{12}+\frac{x-1)/6 =(x+2)/9-1 ?

The answer to (x-3}{12}+\frac{x-1)/6 =(x+2)/9-1 is x=-13/5

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(x-3}{12}+\frac{x-1)/6 =(x+2)/9-1

\frac{x - 3}{12} + \frac{x - 1}{6} = \frac{x + 2}{9} - 1

x = - \frac{13}{5}

Decimal Notation

x = - 2.6

Solution steps

\frac{x - 3}{12} + \frac{x - 1}{6} = \frac{x + 2}{9} - 1

Multiply by LCM

3 (x - 3) + 6 (x - 1) = 4 (x + 2) - 36

Expand

3 (x - 3) + 6 (x - 1) : 9 x - 15

Expand

4 (x + 2) - 36 : 4 x - 28

9 x - 15 = 4 x - 28

Move

15

to the right side

9 x = 4 x - 13

Move

4 x

to the left side

5 x = - 13

Divide both sides by

5

x = - \frac{13}{5}

16 + 7 y - 5 + y = 11 y - 3 - y

- 17 c = - 19 c - 10

x, 5 x + 5 y = 5

x, 5 x + 5 y = 0

- \frac{1}{4} = \frac{1}{5} - \frac{1}{3} a

What is the answer to (x-3}{12}+\frac{x-1)/6 =(x+2)/9-1 ?
The answer to (x-3}{12}+\frac{x-1)/6 =(x+2)/9-1 is x=-13/5
Solve for x: (x-3}{12}+\frac{x-1)/6 =(x+2)/9-1
The solution is x=-13/5